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Reliability and Survival Methods > Degradation > Destructive Degradation
Publication date: 04/30/2021

Destructive Degradation

To measure a product characteristic, sometimes the product must be destroyed. For example, when measuring breaking strength, the product is stressed until it breaks. Regular degradation analysis no longer applies in these situations. You can handle these situations in one of two ways:

If your failure time model is a standard one, it might be covered by the Destructive Degradation platform. See Destructive Degradation.

If you are using custom transformations of the time or response variables and custom nonlinear models, use the Degradation platform. In the launch window, select the Destructive Degradation tab.

Example of Accelerated Destructive Degradation

The following example fits a custom nonlinear model. The data consist of measurements on the strength of an adhesive bond. The product is stressed until the bond breaks, and the required breaking strength is recorded. Because units at normal use conditions are unlikely to break, the units were tested at several levels of an acceleration factor (temperature). You want to estimate the strength (in newtons) of units after 52 weeks (one year) at use conditions of 25oC.

Complete the Launch Window

1. Select Help > Sample Data Library and open Reliability/Adhesive Bond.jmp.

2. Select Analyze > Reliability and Survival > Degradation.

3. Select the Destructive Degradation tab.

4. Select Strength and click Y, Response.

5. Select Weeks and click Time.

6. Select Degrees and click X.

7. Select Censor and click Censor.

Figure 7.18 Completed Launch Window 

8. Click OK.

Define and Fit the Model

1. Select Lognormal from the menu in the Location Parameter Path Specification panel in the Model Specification outline.

This specifies a lognormal transformation for the response, Strength.

2. Click the Degradation Data Analysis red triangle and select Degradation Path Style > Nonlinear Path.

This adds a script window to the report. You insert a script that specifies your model in this window.

3. Copy the JSL formula below and paste it into the script window under Nonlinear Path:

Parameter(
	{b1 = 50, b2 = 50, b3 = -1},
	b1 * :Degrees + b2 * Exp( b3 * Sqrt( :Weeks ) )
)

The script defines a model for Strength in terms of parameters b1, b2, and b3. The script specifies initial values for the parameters.

4. In the text box at the bottom of the report, change Empty to Custom Model.

Figure 7.19 Nonlinear Path Script 

5. Click Use & Save.

Figure 7.20 Updated Model Specification Outline 

The report is updated to include controls for changing initial values for the parameters. Initial values for the parameters are set to the values specified in the formula in the script editor.

6. Click Fit Model.

Figure 7.21 Plot of Fitted Model 

The Parameter panel in the Model Specification outline is updated to show the parameter estimates for the fitted model. The model fit is shown in the Overlay plot. You can drag the axes to show the points, as is done in Figure 7.21. The legend identifies the curves.

Obtain Predicted Values and Prediction Intervals

Next, you obtain a predicted value and prediction interval for Strength after 52 weeks at the baseline use condition of 25oC.

1. Click the Degradation Data Analysis red triangle and select Prediction Settings.

2. In the Prediction Settings window:

Enter 25 for Baseline.

Enter 52 for Time in the Longitudinal Prediction panel.

Select Prediction Interval from the menu in the Longitudinal Prediction panel.

Figure 7.22 Prediction Settings 

3. Click OK.

4. Select the Prediction Graph tab in the report.

Figure 7.23 Prediction Plot at Weeks = 52 

The Prediction Plot shows the predicted value and its 95% level prediction interval above the axis label of 25 (Baseline).

5. Click the Prediction Plot red triangle and select Save Predictions.

Predicted values for the three values of Degrees and for the desired baseline of 25 degrees are saved to a data table. The predicted strength of the adhesive bond after 1 year at 25o C is 61.96, with a prediction interval of 42.42 to 90.50.

Want more information? Have questions? Get answers in the JMP User Community (community.jmp.com).